Introductory Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-805-X
ISBN 13: 978-0-13417-805-9

Chapter 4 - Test - Page 339: 5



Work Step by Step

x=y+4 Plug this value for x into the other equation 3x+7y=-18 3(y+4)+7y=-18 3y+12+7y=-18 3y+7y+12=-18 10y+12=-18 10y+12-12=-18-12 10y=-30 y=-$\frac{30}{10}$ y=-3 Plug this value for y into the first equation to find x x=(-3)+4 x=1 Therefore the solution is {(1,-3)}
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