## Introductory Algebra for College Students (7th Edition)

x=y+4 Plug this value for x into the other equation 3x+7y=-18 3(y+4)+7y=-18 3y+12+7y=-18 3y+7y+12=-18 10y+12=-18 10y+12-12=-18-12 10y=-30 y=-$\frac{30}{10}$ y=-3 Plug this value for y into the first equation to find x x=(-3)+4 x=1 Therefore the solution is {(1,-3)}