Answer
The solution is $(3, 1)$.
Work Step by Step
The coefficients of the $x$ term differ only in sign, so if we add these equations without modification, we will cancel out the $x$ term and can then solve for $y$:
Let us add the equations. First, we cancel out the $x$ term:
$5x - y = 14$
$-5x + 2y = -13$
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$-y = 14$
$2y = -13$
Now we add both sides of the two equations to get:
$y = 1$
Now that we have the value for $y$, we can plug this value into one of the equations to solve for $x$. Let's use the first equation:
$5x - 1 = 14$
Add $1$ to each side of the equation to isolate the variable on one side of the equation and constants on the other:
$5x = 15$
Divide each side of the equation by $5$ to solve for $x$:
$x = 3$
The solution is $(3, 1)$.
