Introductory Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-805-X
ISBN 13: 978-0-13417-805-9

Chapter 4 - Cumulative Review Exercises - Page 340: 11



Work Step by Step

y=4x-8 Plug the value for y into the other equation 2x-3y=9 2x-3(4x-8)=9 2x-12x+24=9 -10x+24=9 -10x=9-24 -10x=-15 x=$\frac{-15}{-10}$ x=$\frac{15}{10}$ x=$\frac{3}{2}$ Plug this value for x into the first equation. y=4($\frac{3}{2}$)-8 y=$\frac{12}{2}$-8 y=6-8 y=-2 Therefore the solution is {($\frac{3}{2}$,-2)}
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.