Introductory Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-805-X
ISBN 13: 978-0-13417-805-9

Chapter 3 - Section 3.1 - Graphing Linear Equations in Two Variables - Exercise Set - Page 220: 46

Answer

$(0,0)$ is a solution, $(1,\displaystyle \frac{1}{5})$ is not a solution, $(2,-\displaystyle \frac{2}{5})$ is a solution.

Work Step by Step

An ordered pair (a,b) is a solution of an equation in x and y if, substituting a for x and b for y, we obtain an equation that holds true. Another way of stating this is that (a,b) satisfies the equation. --- $(x,y)=(0,0)$ $(0)+5(0)=0$ $ 0+0=0 \qquad$ .... true, a solution $(x,y)=(1,\displaystyle \frac{1}{5})$ $(0)+5(\displaystyle \frac{1}{5})=0$ $ 1+1=0 \qquad$ .... false, not a solution $(x,y)=(2,-\displaystyle \frac{2}{5})$ $(2)+5(-\displaystyle \frac{2}{5})=0$ $ 2-2=0 \qquad$ .... true, a solution
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