## Introductory Algebra for College Students (7th Edition)

[3(12$\div$2$^2$-3)$^2$]$^2$ First solve the exponent inside the parentheses. [3(12$\div$4-3)$^2$]$^2$ Then divide inside the parentheses [3(3-3)$^2$]$^2$ Then subtract inside the parentheses [3(0)$^2$]$^2$ Then square the parentheses [3(0)]$^2$ Then multiply the parentheses by the coefficient of 3 [0]$^2$ Then square the brackets 0