Introductory Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-805-X
ISBN 13: 978-0-13417-805-9

Chapter 2 - Section 2.6 - Problem Solving in Geometry - Exercise Set - Page 181: 94

Answer

0

Work Step by Step

[3(12$\div$2$^2$-3)$^2$]$^2$ First solve the exponent inside the parentheses. [3(12$\div$4-3)$^2$]$^2$ Then divide inside the parentheses [3(3-3)$^2$]$^2$ Then subtract inside the parentheses [3(0)$^2$]$^2$ Then square the parentheses [3(0)]$^2$ Then multiply the parentheses by the coefficient of 3 [0]$^2$ Then square the brackets 0
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