#### Answer

0

#### Work Step by Step

[3(12$\div$2$^2$-3)$^2$]$^2$
First solve the exponent inside the parentheses.
[3(12$\div$4-3)$^2$]$^2$
Then divide inside the parentheses
[3(3-3)$^2$]$^2$
Then subtract inside the parentheses
[3(0)$^2$]$^2$
Then square the parentheses
[3(0)]$^2$
Then multiply the parentheses by the coefficient of 3
[0]$^2$
Then square the brackets
0