Introductory Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-805-X
ISBN 13: 978-0-13417-805-9

Chapter 2 - Section 2.6 - Problem Solving in Geometry - Exercise Set - Page 178: 28


h=$\frac{3V}{\pi r^2}$

Work Step by Step

V=$\frac{1}{3}$$\pi$r$^2$h 3(V)=$\pi$r$^2$h $\frac{3V}{\pi r^2}$=$\frac{\pi r^2h}{\pi r^2}$ $\frac{3V}{\pi r^2}$=h h=$\frac{3V}{\pi r^2}$
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