Introductory Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-805-X
ISBN 13: 978-0-13417-805-9

Chapter 2 - Section 2.4 - Formulas and Percents - Exercise Set - Page 155: 84

Answer

The solution is: $$x = 12$$ To check if the solution is correct, we plug $12$ in for $x$ into the original equation to see if both sides of the equation are equal: $$5(12) + 20 = 8(12) - 16$$ We simplify the equation by doing the multiplication first: $$60 + 20 = 96 - 16$$ We then do the addition and subtraction: $$80 = 80$$ Both sides are equal, so we know that the solution is correct.

Work Step by Step

To solve this equation, we need to isolate $x$ on one side of the equation and the constants on the other side. We need to first subtract $5x$ on both sides to move all $x$ terms to one side of the equation: $$20 = 3x - 16$$ We then add $16$ to both sides to move the constants to the other side of the equation: $$3x = 36$$ To isolate $x$, divide by $3$ on both sides: $$x = 12$$ To check if the solution is correct, we plug $12$ in for $x$ into the original equation to see if both sides of the equation are equal: $$5(12) + 20 = 8(12) - 16$$ We simplify the equation by doing the multiplication first: $$60 + 20 = 96 - 16$$ We then do the addition and subtraction: $$80 = 80$$ Both sides are equal, so we know that the solution is correct.
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.