Introductory Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-805-X
ISBN 13: 978-0-13417-805-9

Chapter 2 - Review Exercises - Page 204: 57


7608 m$^2$

Work Step by Step

This figure consists of a large rectangle with two smaller and congruent rectangles cut out of it. The smaller rectangles have the dimensions of 12 m by 75 m. The large rectangle has a width of 64 m and a length equal to 36+75+36, which is 147 m. Therefore the area of the figure is equal the area of the large rectangle minus the areas of the smaller rectangles. A=WL-2wl A=64(147)-2(12)(75) A=64(147)-(24)(75) A=9408-(24)(75) A=9408-1800 A=7608 m$^2$
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