Introductory Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-805-X
ISBN 13: 978-0-13417-805-9

Chapter 1 - Section 1.6 - Subtraction of Real Numbers - Exercise Set - Page 73: 131

Answer

$2$ is not a solution of this equation.

Work Step by Step

If we want to see if $2$ is a solution of this equation, we plug in $2$ to see if both sides of the equation equal one another: $$13(2) + 3 = 3(5(2) - 1)$$ Simplify what is in parentheses first: $$13(2) + 3 = 3(10 - 1)$$ Evaluate what is in parentheses: $$13(2) + 3 = 3(9)$$ Multiply: $$26 + 3 = 27$$ $$29 = 27$$ We see that both sides of the equation do not equal, so $2$ is not a solution of this equation.
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