Introductory Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-805-X
ISBN 13: 978-0-13417-805-9

Chapter 1 - Section 1.5 - Addition of Real Numbers - Exercise Set - Page 64: 79

Answer

a) $\$1,300$ billion b) $\$680$ billion c) $\$1980$ billion

Work Step by Step

a) Since the numbers in the given expression, $ 2303+(-3603) ,$ have different signs, then subtract the numbers and copy the sign of the number with the greater absolute value. That is, \begin{array}{l}\require{cancel} 2303+(-3603) \\= -(1300) \\= -1300 .\end{array} Hence, the deficit is $ \$1,300$ billion. b) The conditions of the problem translates to the expression $ 2775+(-3455) .$ Since the numbers in the expression above have different signs, subtract the numbers and copy the sign of the number with the greater absolute value. That is, \begin{array}{l}\require{cancel} 2775+(-3455) \\= -(680) \\= -680 .\end{array} Hence, the deficit is $ \$680$ billion. c) Adding the deficits in parts (a) and (b) results to the expression, $ -1300+(-680) .$ Since the numbers in the expression above have the same signs, then add the numbers and copy their common. That is, \begin{array}{l}\require{cancel} -1300+(-680) \\= -(1980) \\= -1980 .\end{array} Hence, the combined deficit is $ \$1980$ billion.
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