Introductory Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-805-X
ISBN 13: 978-0-13417-805-9

Chapter 1 - Section 1.2 - Fractions in Algebra - Exercise Set - Page 29: 34

Answer

$\displaystyle \frac{9}{10}$

Work Step by Step

Reducing a Fraction to Its Lowest Terms 1. Write the prime factorizations of the numerator and the denominator. 2. Divide the numerator and the denominator by the greatest common factor, the product of all factors common to both. --- $\begin{array}{lllll} 45 & =9\times 5 & ... & 50 & =2\times 25\\ & =3\times 3\times 5 & & & =2\times 5\times 5\\ & & GCF=5 & & \end{array}$ $\displaystyle \frac{45}{50}=\frac{45\div 5}{50\div 5}=\frac{9}{10}$
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