## Introductory Algebra for College Students (7th Edition)

Substituting $A=200$ in the given model, $H=0.8(200-A) ,$ then \begin{array}{l}\require{cancel} H=0.8(200-200) \\ H=0.8(0) \\ H=0 .\end{array} Since $H=0,$ then this means that there is no handicapping.