Introductory Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-805-X
ISBN 13: 978-0-13417-805-9

Chapter 1 - Section 1.1 - Introduction to Algebra: Variables and Mathematical Models - Exercise Set - Page 13: 98


there is no handicapping

Work Step by Step

Substituting $A=200$ in the given model, $ H=0.8(200-A) ,$ then \begin{array}{l}\require{cancel} H=0.8(200-200) \\ H=0.8(0) \\ H=0 .\end{array} Since $H=0,$ then this means that there is no handicapping.
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