Answer
there is no handicapping
Work Step by Step
Substituting $A=200$ in the given model, $
H=0.8(200-A)
,$ then
\begin{array}{l}\require{cancel}
H=0.8(200-200)
\\
H=0.8(0)
\\
H=0
.\end{array}
Since $H=0,$ then this means that there is no handicapping.
