Introductory Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-805-X
ISBN 13: 978-0-13417-805-9

Chapter 1 - Review Exercises: 97

Answer

-$\frac{20}{3}$

Work Step by Step

($\frac{1}{2}$+$\frac{1}{3}$)$\div$($\frac{1}{4}$-$\frac{3}{8}$) First make the sets of fractions have common denominators. ($\frac{1(3)}{2(3)}$+$\frac{1(2)}{3(2)}$)$\div$($\frac{1(2)}{4(2)}$-$\frac{3}{8}$) ($\frac{3}{6}$+$\frac{2}{6}$)$\div$($\frac{2}{8}$-$\frac{3}{8}$) Then add and subtract inside the sets of parentheses. ($\frac{5}{6}$)$\div$(-$\frac{1}{8}$) Then change the division to multiplication of the reciprocal of the divisor. ($\frac{5}{6}$)$\times$(-$\frac{8}{1}$) Then multiply.. -$\frac{40}{6}$ Then reduce by 2. -$\frac{20}{3}$
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