#### Answer

$x(x+1)$ or $x^2+x$

#### Work Step by Step

RECALL:
$\log_b{x}+\log_b{y} =\log_b{(xy)}$
Use the rule above to obtain:
$\log_3{[x(x+1)]}=2$
Thus, the missing expression in the given statement is:
$x(x+1)$ or, when multiplied, $x^2+x$

Published by
Pearson

ISBN 10:
0-13417-894-7

ISBN 13:
978-0-13417-894-3

$x(x+1)$ or $x^2+x$

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