Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 9 - Section 9.4 - Properties of Logarithms - Exercise Set - Page 715: 125

Answer

$64$.

Work Step by Step

$=16^{\frac{3}{2}}$ We can write $16=4^2$ The expression becomes $=(4^2)^{\frac{3}{2}}$ Multiply powers. $=(4)^{2\cdot \frac{3}{2}}$ Simplify. $=(4)^{3}$ $=4\cdot 4\cdot 4 $ $=64$.
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