Answer
False
Work Step by Step
To prove: $\dfrac{\log_7{49}}{\log_7{7}}=\log_7{49}-\log_7 {7}$
This can be written as:
$\dfrac{\log_7{7^2}}{1}=\log_7{7^2}-1$
Since,$\log_a a^b=b$
or, $2=2-1$
or, 2=1$; which is not true
Hence, the statement is false.
