Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 9 - Section 9.1 - Exponential Functions - Exercise Set - Page 672: 42

Answer

$8.25\%$ Compounded quarterly.

Work Step by Step

Investment $P=\$6,000$. Time $t=4$ years. $8.25\%$ Compounded quarterly $(n=4)$ Rate of interest $r=8.25\%=0.0825$. Compounded interest formula $A=P\left ( 1+\frac{r}{n} \right )^{nt}$ Substitute all values. $A_1=6,000\left ( 1+\frac{0.0825}{4} \right )^{4\cdot 4}$ $A_1=6,000\left ( \frac{4+0.0825}{4} \right )^{16}$ $A_1=6,000\left ( \frac{4.0825}{4} \right )^{16}$ $A_1=6,000\left ( 1.38630641625 \right )$ $A_1=8317.83849752$. $8.3\%$ Compounded semiannually $(n=2)$ Rate of interest $r=8.3\%=0.083$. Compounded interest formula $A=P\left ( 1+\frac{r}{n} \right )^{nt}$ Substitute all values. $A_2=6,000\left ( 1+\frac{0.083}{2} \right )^{2\cdot 4}$ $A_2=6,000\left ( \frac{2+0.083}{2} \right )^{8}$ $A_2=6,000\left ( \frac{2.083}{2} \right )^{8}$ $A_2=6,000\left ( 1.38444017722 \right )$ $A_2=8306.6410633$. By comparing both values $A_1>A_2$.
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