Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 9 - Review Exercises - Page 750: 33

Answer

$\frac{1}{2}$

Work Step by Step

The power rule for logarithms says that $\log_b{M^p}=p\log_bM$ i.e. the logarithm of a number with an exponent is the exponent times the logarithm of the number. Also $\log_a a^n=n$ if $a\ne1,a\gt0$. Hence here: $\log_{16}{4}=\log_{16}{16^{\frac{1}{2}}}=\frac{1}{2}$
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