Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 9 - Mid-Chapter Check Point: 31

Answer

$19+20 \cdot \ln{x}$

Work Step by Step

RECALL: (1) $\log_b{(\frac{m}{n})}=\log_b{m} - \log_b{n}$ (2) $\log_b{(mn)}=\log_b{m} + \log_b{n}$ (3) $\log_b{(b^x)}=x$ (4) $\log_b{(m^n)}=n \cdot \log_b{m}$ (5) $\sqrt{a} = a^{\frac{1}{2}}$ With $b=e$, use rule (2) above to obtain: $=\ln{(e^{19})}+\ln{(x^{20})}$ Use rule (3) above with $b=e$ to obtain: $=19+\ln{(x^{20})}$ Use rule (4) above to obtain: $=19+20 \cdot \ln{x}$
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