Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 8 - Section 8.2 - The Quadratic Formula - Exercise Set - Page 610: 101


Makes sense. $±\sqrt {b^2-4ac} = ±17i$ Therefore, there are two solutions: $+17i$ and $-17i$.

Work Step by Step

The discriminant is the part of the quadratic formula under the radical sign: $b^2-4ac$. The discriminant determines the number of solutions in a given equation. For instance, if: $b^2-4ac = 0$, then there is one real number solution. $b^2-4ac =$ $negative$ $number$, then there are two imaginary solutions. $b^2-4ac =$ $positive$ $number$, then there are two real number solutions. Thus, obtaining a value of $-17$ only means that there are two imaginary solutions, $+17i$ and $-17i$.
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