## Intermediate Algebra for College Students (7th Edition)

$4.47$ miles (approximately)
Apply Pythagorean theorem. $c^2=a^2+b^2$ Plug $a=4$ miles and $b= 2$ miles. We have $c^2=4^2+2^2=16+4$ or, $c^2=20$ or, $c=\sqrt {20}$ or, $c=2\sqrt 5$ or $c=4.47$ miles (approximately)