Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 7 - Section 7.7 - Complex Numbers - Exercise Set - Page 572: 145

Answer

$x=\frac{yz}{y-z}$

Work Step by Step

LCD$=xyz$, thus multiplying both sides by the LCD: $\frac{1}{x}+\frac{1}{y}=\frac{1}{z}\\yz+xz=xy\\yz=xy-xz\\yz=x(y-z)\\x=\frac{yz}{y-z}$
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