Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 7 - Section 7.5 - Multiplying with More Than One Term and Rationalizing Denominators - Exercise Set - Page 552: 143

Answer

$\left \{\frac{45}{7}\right \}$.

Work Step by Step

The given equation is $\Rightarrow 7[(2x-5)-(x+1)]=(\sqrt7+2)(\sqrt7-2)$ Use the special formula $(A+B)(A-B)=A^2-B^2$ $\Rightarrow 7[2x-5-x-1]=(\sqrt7)^2-(2)^2$ Simplify. $\Rightarrow 7[x-6]=7-4$ Use the distributive property. $\Rightarrow 7x-42=3$ Add $42$ to both sides. $\Rightarrow 7x-42+42=3+42$ Simplify. $\Rightarrow 7x=45$ Divide both sides by $7$. $\Rightarrow \frac{7x}{7}=\frac{45}{7}$ Simplify. $\Rightarrow x=\frac{45}{7}$ The solution set is $\left \{\frac{45}{7}\right \}$.
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