Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 7 - Section 7.5 - Multiplying with More Than One Term and Rationalizing Denominators - Exercise Set: 3

Answer

$7\sqrt{6} - 6$

Work Step by Step

RECALL: (1) Distributive Property: For any real numbers a, b, and c, $a(b-c) = ab - ac$ (2) For any real numbers real numbers a and b within the domain, $\sqrt[n]{a} \cdot \sqrt[n]{b} = \sqrt[n]{ab}$ (3) $\sqrt{a} \cdot \sqrt{a} = a, a \ge 0$ Use rule (1) above to obtain: $=\sqrt{6} \cdot 7 - \sqrt{6} \cdot \sqrt{6} \\=7\sqrt{6} - \sqrt{6} \cdot \sqrt{6}$ Use rule (3) above to obtain: $=7\sqrt{6} - 6$
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