Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 7 - Section 7.2 - Rational Exponents - Exercise Set - Page 525: 163

Answer

a ) Since, $\sqrt{16} \sqrt{4}=8$ b) Since, $\sqrt{(16)(4)}=8$ c) $\sqrt{ab}=\sqrt a \sqrt b$

Work Step by Step

a ) Since, $\sqrt{16} \sqrt{4}=(16)^{1/2} (4)^{1/2}=(4^2)^{1/2} (2^2)^{1/2}= (4)(2)=8$ b) Since, $\sqrt{(16)(4)}=(64)^{1/2}=(8^2)^{1/2}=8$ c) It is true that $\sqrt{ab}=\sqrt a \sqrt b$
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