Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 7 - Section 7.2 - Rational Exponents - Concept and Vocabulary Check - Page 521: 2



Work Step by Step

$\sqrt[n] {a^n}=a$ if $n$ is odd. $8=2^3$, so $\sqrt[3]{8}=\sqrt[3]{2^3}=2$. Thus $8^{\frac{1}{3}}=\sqrt[3]{2^3}=2$
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