Answer
$3$
Work Step by Step
Simplify. $\sqrt[3]{\sqrt [4]{16}+\sqrt{625}}$
or, $=\sqrt[3]{\sqrt [4]{2^4}+\sqrt{25 \cdot 25}}$
or, $=\sqrt[3]{2+25}$
or, $=\sqrt[3]{27}$
or, $=\sqrt[3]{3^3}$
or, $=3$
Intermediate Algebra for College Students (7th Edition)
by Blitzer, Robert F.
Published by
Pearson
ISBN 10:
0-13417-894-7
ISBN 13:
978-0-13417-894-3
Chapter 7 - Section 7.1 - Radical Expressions and Functions - Exercise Set - Page 513: 99
Update this answer!
You can help us out by revising, improving and updating this answer.
Update this answerAfter you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.
