Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 7 - Section 7.1 - Radical Expressions and Functions - Exercise Set - Page 512: 58

Answer

$g(13)=-3$ $g(0)=-1$ $g(-63)=5$.

Work Step by Step

The given function is $g(x)=-\sqrt[3] {2x+1}$ Plug $x=13$ into the function. $g(13)=-\sqrt[3] {2(13)+1}$ Simplify. $g(13)=-\sqrt[3] {26+1}$ $g(13)=-\sqrt[3] {27}$ $g(13)=-\sqrt[3] {3^3}$ $g(13)=-3$ Plug $x=0$ into the function. $g(0)=-\sqrt[3] {2(0)+1}$ Simplify. $g(0)=-\sqrt[3] {0+1}$ $g(0)=-\sqrt[3] {1}$ $g(0)=-\sqrt[3] {1^3}$ $g(0)=-1$ Plug $x=-63$ into the function. $g(-63)=-\sqrt[3] {2(-63)+1}$ Simplify. $g(-63)=-\sqrt[3] {-126+1}$ $g(-63)=-\sqrt[3] {-125}$ $g(-63)=-\sqrt[3] {(-5)^3}$ $g(-63)=-(-5)$ $g(-63)=5$.
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