Answer
$g(13)=-3$
$g(0)=-1$
$g(-63)=5$.
Work Step by Step
The given function is
$g(x)=-\sqrt[3] {2x+1}$
Plug $x=13$ into the function.
$g(13)=-\sqrt[3] {2(13)+1}$
Simplify.
$g(13)=-\sqrt[3] {26+1}$
$g(13)=-\sqrt[3] {27}$
$g(13)=-\sqrt[3] {3^3}$
$g(13)=-3$
Plug $x=0$ into the function.
$g(0)=-\sqrt[3] {2(0)+1}$
Simplify.
$g(0)=-\sqrt[3] {0+1}$
$g(0)=-\sqrt[3] {1}$
$g(0)=-\sqrt[3] {1^3}$
$g(0)=-1$
Plug $x=-63$ into the function.
$g(-63)=-\sqrt[3] {2(-63)+1}$
Simplify.
$g(-63)=-\sqrt[3] {-126+1}$
$g(-63)=-\sqrt[3] {-125}$
$g(-63)=-\sqrt[3] {(-5)^3}$
$g(-63)=-(-5)$
$g(-63)=5$.