Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 7 - Section 7.1 - Radical Expressions and Functions - Exercise Set - Page 511: 7

Answer

$\dfrac{1}{5}$

Work Step by Step

Recall, square roots cancel out exponents of two. Thus, we obtain: $=\sqrt{\frac{1}{25}}\\\\=\sqrt{\left(\dfrac{1}{5}\right)^2} \\=\dfrac{1}{5}$
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