#### Answer

$(-\infty, +\infty)$

#### Work Step by Step

For any real number $x$, $\sqrt[3]{x}$ exists (or is defined).
Thus, the domain of $f(x)=\sqrt[3]{x}$ is the set of all real numbers.
In interval notation, the domain is $(-\infty, +\infty)$.

Published by
Pearson

ISBN 10:
0-13417-894-7

ISBN 13:
978-0-13417-894-3

$(-\infty, +\infty)$

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