Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 6 - Section 6.6 - Rational Equations - Exercise Set - Page 462: 7

Answer

$x=-4$

Work Step by Step

LCD$=(x+1)(x-1)$, thus multiplying both sides by the LCD: $(x+1)(x-1)(\frac{3}{x+1})=(x+1)(x-1)(\frac{5}{x-1})\\3(x-1)=5(x+1)\\3x-3=5x+5\\-2x=8x\\x=-4$
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