Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 6 - Section 6.5 - Synthetic Division and the Remainder Theorem - Exercise Set - Page 455: 55


See below.

Work Step by Step

$2x(x+3)+6(x-3)=28\\2x^2+6x+6x-18=-28\\2x^2+12x+10=0\\x^2+6x+5=0\\x^2+x+5x+5=0\\x(x+1)+5(x+1)=0\\(x+1)(x+5)=0$ Thus $x=-1$ or $x=5$.
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