## Intermediate Algebra for College Students (7th Edition)

$2x(x+3)+6(x-3)=28\\2x^2+6x+6x-18=-28\\2x^2+12x+10=0\\x^2+6x+5=0\\x^2+x+5x+5=0\\x(x+1)+5(x+1)=0\\(x+1)(x+5)=0$ Thus $x=-1$ or $x=5$.