Answer
$x=3$ or $x=9$.
Work Step by Step
$x^2+27=12x\\x^2-3x-9x+27=0\\x(x-3)-9(x-3)=0\\(x-3)(x-9)=0$,
so $x=3$ or $x=9$.
Intermediate Algebra for College Students (7th Edition)
by Blitzer, Robert F.
Published by
Pearson
ISBN 10:
0-13417-894-7
ISBN 13:
978-0-13417-894-3
Chapter 6 - Section 6.3 - Complex Rational Expressions - Exercise Set - Page 438: 71
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