Answer
$\frac{x-y+1}{(x-y)(x-y)}$.
Work Step by Step
The given expression is
$\Rightarrow (x-y)^{-1}+(x-y)^{-2}$
Write the negative power as a fraction.
$\Rightarrow \frac{1}{(x-y)}+\frac{1}{(x-y)^{2}}$
Or we can write:
$\Rightarrow \frac{1}{(x-y)}+\frac{1}{(x-y)(x-y)}$
The LCD of the denominators is $(x-y)(x-y)$
Multiply the numerator and the denominator of the first fraction
$\Rightarrow \frac{(x-y)}{(x-y)(x-y)}+\frac{1}{(x-y)(x-y)}$
$\Rightarrow \frac{(x-y)}{(x-y)(x-y)}+\frac{1}{(x-y)(x-y)}$
Add the numerators because the denominators are equal.
$\Rightarrow \frac{x-y+1}{(x-y)(x-y)}$.
