Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 6 - Section 6.1 - Rational Expressions and Functions; Multiplying and Dividing - Exercise Set - Page 417: 149

Answer

$16a^{8}b^{26}c^{2 }$.

Work Step by Step

$\Rightarrow \left (\frac{ab^{-3}c^{-4}}{4a^5b^{10}c^{-3}} \right )^{-2}$ Simplify inside the parentheses. Subtract the exponents when dividing. $\Rightarrow \left (2^{-2}a^{1-5}b^{-3-10}c^{-4+3} \right )^{-2}$ Simplify. $\Rightarrow \left (2^{-2}a^{-4}b^{-13}c^{-1} \right )^{-2}$ Negative square each factor in parentheses. $\Rightarrow (2^{-2})^{-2}(a^{-4})^{-2}(b^{-13})^{-2}(c^{-1} )^{-2}$ Multiply the exponents when raising a power to a power. $\Rightarrow 2^{4}a^{8}b^{26}c^{2 }$ Simplify. $\Rightarrow 16a^{8}b^{26}c^{2 }$.
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