Answer
$x^3+y^3-4x^2y+2xy^2$
Work Step by Step
Given: $(x-y)(x^2-3xy-y^2)$
Need to the multiply the polynomials.
$=x(x^2-3xy-y^2)-y(x^2-3xy-y^2)$
$=x^3-3x^2y-xy^2-x^2y+3xy^2+y^3$
Hence, $=x^3+y^3-4x^2y+2xy^2$
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