Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 5 - Test - Page 401: 9

Answer

$x^3+y^3-4x^2y+2xy^2$

Work Step by Step

Given: $(x-y)(x^2-3xy-y^2)$ Need to the multiply the polynomials. $=x(x^2-3xy-y^2)-y(x^2-3xy-y^2)$ $=x^3-3x^2y-xy^2-x^2y+3xy^2+y^3$ Hence, $=x^3+y^3-4x^2y+2xy^2$
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