Answer
$f(0)=6$ and $f(-2)=4$
Work Step by Step
Given: $f(x)=3x^3+5x^2-x+6$
Plug $x=0$ in the above polynomial
$f(0)=3(0)^3+5(0)^2-0+6=6$
and $f(x)=3x^3+5x^2-x+6$
Plug $x=-2$ in the above polynomial
$f(-2)=3(-2)^3+5(-2)^2-(-2)+6=-24+20+8=4$