Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 5 - Section 5.6 - A General Factoring Strategy - Exercise Set - Page 380: 107

Answer

The solution set is $\{-1\}$.

Work Step by Step

Multiply both sides of the given equation by the least common denominator of the fractions (which is $10$) to clear fractions. $10\left (\frac{3x-1}{5}+\frac{x+2}{2}\right )=10\left (-\frac{3}{10} \right )$ Use the distributive property . $10\left (\frac{3x-1}{5}\right )+10 \left (\frac{x+2}{2}\right )=10\left (-\frac{3}{10} \right )$ Simplify. $2(3x-1)+5 (x+2 )=-3$ Use the distributive property and clear the parentheses. $6x-2+5x+10=-3$ Add like terms. $11x+8=-3$ Subtract $8$ from both sides. $11x+8-8=-3-8$ Add like terms. $11x=-11$ Divide both sides by $11$. $\frac{11x}{11}=\frac{-11}{11}$ Simplify. $x=-1$.
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