Answer
$(x^n+y^{4n})(x^{2n}-x^ny^{4n}+y^{8n})$
Work Step by Step
The formula for factoring the sum of two cubes is: $A^3+B^3=(A+B)(A^2-AB+B^2)$.
Hence here: $x^{3n}+y^{12n}=(x^n)^3-(y^{4n})^3=(x^n+y^{4n})(x^{2n}-x^ny^{4n}+y^{8n})$
Intermediate Algebra for College Students (7th Edition)
by Blitzer, Robert F.
Published by
Pearson
ISBN 10:
0-13417-894-7
ISBN 13:
978-0-13417-894-3
Chapter 5 - Section 5.5 - Factoring Special Forms - Exercise Set - Page 373: 135
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