Answer
$(x-4)(x^2+4x+16)$
Work Step by Step
The formula for factoring the difference of two cubes is: $A^3-B^3=(A-B)(A^2+AB+B^2)$.
Hence here: $x^3-64=x^3-4^3=(x-4)(x^2+4x+16)$, thus the statement is false.
Intermediate Algebra for College Students (7th Edition)
by Blitzer, Robert F.
Published by
Pearson
ISBN 10:
0-13417-894-7
ISBN 13:
978-0-13417-894-3
Chapter 5 - Section 5.5 - Factoring Special Forms - Exercise Set - Page 373: 131
Update this answer!
You can help us out by revising, improving and updating this answer.
Update this answerAfter you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.
