Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 5 - Section 5.2 - Multiplication of Polynomials - Exercise Set - Page 341: 147

Answer

$9$ and $11$.

Work Step by Step

Let the smaller integer be $x$. The larger integer is $x+2$. From question we have. $\Rightarrow (x)(x+2)=(x+2)^2-22$ Clear the parentheses and apply the distributive property. $\Rightarrow x^2+2x=x^2+4x+4-22$ Add $-x^2-4x$ to both sides. $\Rightarrow x^2+2x-x^2-4x=x^2+4x+4-22-x^2-4x$ Simplify. $\Rightarrow -2x=-18$ Divide both sides by $-2$. $\Rightarrow \frac{-2x}{-2}=\frac{-18}{-2}$ Simplify. $\Rightarrow x=9$ Smaller integer is $9$. Larger integer is $9+2=11$.
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