Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 5 - Section 5.2 - Multiplication of Polynomials - Exercise Set - Page 337: 26

Answer

$x^3-8$

Work Step by Step

$(x-2)(x^2+2x+4)=\\=x(x^2+2x+4)-2(x^2+2x+4)\\=(x^3+2x^2+4x)+(-2x^2-4x-8)\\=x^3-8$
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