## Intermediate Algebra for College Students (7th Edition)

$=-2x^3y^2-4x^3y-8$
Given:$(4x^3y^2-7x^3y-4)-(6x^3y^2-3x^3y+4)$ This implies $(4x^3y^2-7x^3y-4)-(6x^3y^2-3x^3y+4)=4x^3y^2-7x^3y-4-6x^3y^2+3x^3y-4$ and $=4x^3y^2-6x^3y^2-7x^3y+3x^3y-4-4$ Hence, the result is : $=-2x^3y^2-4x^3y-8$