Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 4 - Section 4.5 - Linear Programming - Exercise Set - Page 303: 1

Answer

The answer is at $(1,2)=17$ at $(2,10)=70 $ at $ (7,5) =65$ at $ (8,3) =58 $ Maximum $ =70 $ and Minimum $=17 $

Work Step by Step

The given objective function is $ z=5x+6y $. The value of the function at each corner points of the graph is shown below. At $(1,2) $ $ z=5(1)+6(2) $ $ z=5+12 $ $ z=17 $. At $(2,10) $ $ z=5(2)+6(10) $ $ z=10+60 $ $ z=70 $. At $(7,5) $ $ z=5(7)+6(5) $ $ z=35+30 $ $ z=65 $. At $(8,3) $ $ z=5(8)+6(3) $ $ z=40+18 $ $ z=58 $. The maximum value of the objective function is $ 70 $. The minimum value of the objective function is $17 $.
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