## Intermediate Algebra for College Students (7th Edition)

Between $[59,95]$
Consider the expression $C=\dfrac{5}{9}(F-32)$ For $C=15$ we have $15=\dfrac{5}{9}(F-32)$ This implies $(15)(\dfrac{9}{5})=F-32$ or, $F=59$ For $C=35$ we have $35=\dfrac{5}{9}(F-32)$ This implies $(35)(\dfrac{9}{5})=F-32$ or, $F=95$ Our result is: Between $[59,95]$