Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 4 - Section 4.1 - Solving Linear Inequalities - Exercise Set - Page 264: 59

Answer

More than $100$ miles must be driven in a day.

Work Step by Step

Let the number of miles per day be $x$. Basic Rental charges is $\$50$ a day plus $\$0.20$ per mile. Continental charges is $\$20$ a day plus $\$0.50$ per mile. In the mathematical form. Basic Rental charges $=50+0.20x$. Continental charges is $=20+0.50x$. For the Basic Rental to be a better deal the inequality is. Continental charges $>$ Basic Rental charges. The inequality is $\Rightarrow 20+0.50x>50+0.20x$. Add $-20-0.20x$ to both sides. $\Rightarrow 20+0.50x-20-0.20x>50+0.20x-20-0.20x$. Simplify. $\Rightarrow 0.30x>30$. Divide both sides by $0.30$. $\Rightarrow \frac{0.30x}{0.30}>\frac{30}{030}$. Simplify. $\Rightarrow x>100$. Hence, more than $100$ miles must be driven in a day.
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