Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 4 - Mid-Chapter Check Point - Page 286: 7

Answer

$\left\{ \frac{1}{2},\frac{13}{4} \right \}$.

Work Step by Step

The given equation is $\Rightarrow \left | x+5\right |=\left | 5x-8\right |$ Rewrite the equation without absolute value bars. $\Rightarrow x+5=5x-8$ or $x+5=-(5x-8)$ Solve both equations separately. First equation. $\Rightarrow x+5=5x-8$ Add $8-x$ to both sides. $\Rightarrow x+5+8-x=5x-8+8-x$ Add like terms. $\Rightarrow 13=4x$ Divide both sides by $4$. $\Rightarrow \frac{13}{4}=\frac{4x}{4}$ Simplify. $\Rightarrow \frac{13}{4}=x$ Switch the values. $\Rightarrow x=\frac{13}{4}$ Second equation. $\Rightarrow x+5=-(5x-8)$ Clear the parentheses. $\Rightarrow x+5=-5x+8$ Add $5x-5$ to both sides. $\Rightarrow x+5+5x-5=-5x+8+5x-5$ Simplify. $\Rightarrow 6x=3$ Divide both sides by $6$. $\Rightarrow \frac{6x}{6}=\frac{3}{6}$ Simplify. $\Rightarrow x=\frac{1}{2}$ Hence, the solution set is $\left\{ \frac{1}{2},\frac{13}{4} \right \}$.
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