Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 3 - Section 3.5 - Determinants and Cramer’s Rule - Exercise Set - Page 242: 79

Answer

The answer is $14$.

Work Step by Step

The given equation is $ \frac{x+3}{4}=\frac{x-2}{3}+\frac{1}{4} $ Multiply both sides by $ 12$. $ 12\cdot (\frac{x+3}{4})= 12\cdot (\frac{x-2}{3})+ 12\cdot (\frac{1}{4}) $ $ 3(x+3)= 4(x-2)+ 3 $ Clear the parentheses. $ 3x+9=4x-8+3 $ Add like terms. $ 3x+9=4x-5 $ Rearrange. $ 9+5=4x-3x $ Add like terms. $ 14=x $.
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