Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 3 - Section 3.5 - Determinants and Cramer’s Rule - Exercise Set - Page 241: 46

Answer

$x=26.$

Work Step by Step

We know that for a matrix \[ \left[\begin{array}{rr} a & b \\ c &d \\ \end{array} \right] \] the determinant, $D=ad-bc.$ Hence here $D=(x+3)\cdot(-4)-(-6)\cdot(x-2)=28\\-4x-12+6x-12=28\\2x-24=28\\2x=52\\x=26.$
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