Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 3 - Section 3.5 - Determinants and Cramer’s Rule - Concept and Vocabulary Check - Page 239: 1

Answer

The fill in the blanks is in red color. $= {\color{Red} 5}\cdot {\color{Red} 3} - {\color{Red} 2}\cdot {\color{Red} 4}={\color{Red} {15}}-{\color{Red} 8}={\color{Red} 7} $ and ${\color{Red} {determinant}}$ is ${\color{Red} 7}$.

Work Step by Step

The given matrix in the determinant form. \begin{vmatrix} 5 & 4\\ 2&3 \end{vmatrix} We multiply and subtract as shown below. $= 5\cdot 3 - 2\cdot 4$ $=15-8 $ $=7 $ this is the second order determinant whose value is $ 7$.
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